Question

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Answer 1

This is very simple.
R2 R3 and R4 are in series add them up.
It is 6ohm.
now this parallel to R1 which is 2ohm.
Calculate the resultant resistance.
It will be 1.5ohm.
hence the resultant resistance is 1.5ohm.
now i=2A
Hope u got that

Answer 2

As We Can See From The Diagram R1 , R1 , R3 are in The Series..

So $R_{T1}$ = $R_{1}$ + $R_{2}$ + $R_{3}$

$R_{T1}$  = 2 + 2 + 2

$R_{T1}$ = 6 Ohms

Now R4 and $R_{T1}$ are Parallel

So,

1/$R_{T}$ = 1/$R_{T1}$ +  1/$R_{4}$

1/$R_{T}$ = 1/6 + 1/2

1/$R_{T}$ = 4/6

$R_{T}$ = 1.5 Ohms

So Now Using Formula...

I = V/R

I = 3/1.5

I = 2 A