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Hey.
The given equation is:
2 N2 (g) + O2 (g) ⇌ 2 N2O (g)
Therefore the equilibrium constant Kc, will be given as:
Kc = [N2O] ^2 / [N2] ^2 [O2]
Since, Kc is very small (2.0 X 10^-37), we can assume x to be infinitesimally small so that,
0.0482 – 2x ≈ 0.0482 and 0.0933 – x ≈ 0.0933
Check the attachment for detailed solution.
The given equation is:
2 N2 (g) + O2 (g) ⇌ 2 N2O (g)
Therefore the equilibrium constant Kc, will be given as:
Kc = [N2O] ^2 / [N2] ^2 [O2]
Since, Kc is very small (2.0 X 10^-37), we can assume x to be infinitesimally small so that,
0.0482 – 2x ≈ 0.0482 and 0.0933 – x ≈ 0.0933
Check the attachment for detailed solution.
Attachments:
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