Question

☺️✨hey guys✨☺️

# ❎❎NO SPAMS❎❎


FOrMUlaE- b^2 - 4ac


⚫3x^2 - 5x - 2
⚫x^2 - 4x - 1
⚫ x^2 + 4Kx + ( K^2 - K +2 )



the 1st one to answer my question completely with any mistakes will be marked as brainliest ✌️❣️

so guys go on ☺️❣️​

Answer 1

Hello!

(1)3x²-5x-2

let, 3x²-5x-2 = 0

Here,

a = 3,

b = -5

c = -2

As we know,

Discriminant(D) = b²-4ac

D = (-5)² -4(3)(-2)

D = 25+24

D = 49

_______________________________

(2) x²-4x-1

let, x²-4x-1 = 0

Here,

a = 1

b = -4

c = -1

Now,

D = (-4)² -4(1)(-1)

D = 16+4

D = 20

_____________________________

(3) x2+4kx+(k²-k+2)

let, x²+4kx+(k²-k+2) = 0

Here,

a = 1

b = 4k

c = k²-k+2

Now,

D = (4k)² -4(1)(k²-k+2)

D = 16k² -4k²-4k-8

D = 12k²-4k-8

[U can factorise it]

Hope it helps!

Answer 2

Answer:

b^2-4ac

1)3x^2-5x-2

(-5)^2-4(3)(-2)

=25+24=49

2)x^2-4x-1

(-4)^2-4(1)(-1)

16+4=20

3)x^2+4kx+(k^2-k+2)

16k^2-4(1)(k^2-k+2)

16k^2-4k^2+4k-8

12k^2+4k-8

If u want u factorise it