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Answer:
Given that the area of the circle = 9π
πr2=9π where r is the radius of the circle
r2=9,r=3
diameter of the circle = 2×3=6
side of the square = 6 units
Area of square = 6 units
Area of PQRS = 62=36 sq.units
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Step-by-step explanation:
Area of circle=πr²
ATQ
πr²=9π
r²=9
r=3
d=3*2=6
Diagonal of the square=Radius of the circle
Area of square with diagonal=1/2*d²=1/2*6²=1/2*36=18
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