Question

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PLEASE ANSWER FAST

a circle of 30 cm diameter has a 24 cm chord what is the distance of the chord from the centre

Answer 1

A perpendicular line from centre bisects the chord
Therefore 1/2chord =12
Its radius =15
Now applying phythagoros therom h²=b²+p²we get root under 225-144=rootunder 81=9

Answer 2

diameter = 30cm
radius = 15cm
chord length=24cm

by theorem perpendicular from the center bisect the chord

the chord is bisected at 90 degree

so the two parts of line of 12cm each

by applying pythagoras theorem

radius^2 = 1 side of Chord^2 + distance ^2

15^2 = 12^2 + x^2

225 = 144 + x^2

x^2= 225-144

x^2=81

x=√81

x=9

so the distance = 9 cm

hope it helps