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Resistance R=Sl/A where S is specific resistivity
l is length and A is area.
So R1/R2= S1/S2 × l1/l2 × (r2)^2/(r1)^2
where r is radius.
So R1/R2 = 1.62×10^-8/4.86×10^-8 × 2l/l × (2r)^2/(r)^2
R1/R2= 1/3 × 2 × 4
R1/R2= 8/3.
or
3R1 = 8R2.
It's implies that R1 is greater than R2 i.e; A has more resistance than B.
Hope this helps you.
l is length and A is area.
So R1/R2= S1/S2 × l1/l2 × (r2)^2/(r1)^2
where r is radius.
So R1/R2 = 1.62×10^-8/4.86×10^-8 × 2l/l × (2r)^2/(r)^2
R1/R2= 1/3 × 2 × 4
R1/R2= 8/3.
or
3R1 = 8R2.
It's implies that R1 is greater than R2 i.e; A has more resistance than B.
Hope this helps you.
abhinavdinesankp:
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here's us answer
perfect solution
plz mark as brainliest
perfect solution
plz mark as brainliest
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