Math, asked by Anonymous, 1 year ago

hey guys please answer my question and I'll mark u brainliest

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Answered by Anonymous
2
In cylinder,

r=7cm=0.7m

l=15km

 =15000m

In tank,

l=50m

b=44m

h=0.21m

Vol.of water in tank=lbh

                               =50*44*0.21

                               =462m³

Height of cylindrical pipe=Vol. / πr²

                                      =462/(0.07)²(22/7)

                                      =462/0.0154

                                      =30000m

Time = 30000/15000

         = 2 hours

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Answered by ranjanalok961
2
rate of flowing water = 15 km/h = 25/6 m/s = length of pipe / h

15 km/h = 15000/60×60 = 25/6 m/s

diameters = 14 cm

radius = 7 cm = 7/100 m

volume of pipe = πr²h here h is length of pipe

volume of pipe = 22/7 × 7/100 × 7/100 × 25/6

now , length of cuboids = 50 m
breath =44
height = 21 cm = 21/100

volume of cuboids = 50×44×21/100

let time is t
then ,

=>t× volume of pipe = volume of cuboids

=> t × 22/7 × 7/100 × 7/100 × 25/6 = 50×44×21/100

=> t × 22×7 / 100× 4 × 6 = 50×44×21/100

=> t × 154 /2400 = 22×21

=> t = 22×21 × 2400 / 154

=> t = 3 × 2400 = 7200 s

=> t = 7200/60 × 60 = 2h


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