Math, asked by Anonymous, 1 year ago

hey guys please answer my question and I'll mark u brainliest

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Answered by 1402Aryan1402

cosA +sinA = √2cosA

squaring

⇒(cosA + sin A)² = (√2cosA)²

⇒cos²A + sin²A + 2sinAcosA = 2cos²A

⇒1 - sin²A + 1 - cos²A + 2sinAcosA = 2cos²A

⇒2 - 2cos²A = cos²A + sin²A - 2sinAcosA

⇒2(1 - cos²A)= (cosA - sinA)²

⇒ cosA - sinA = √[2sin²A]

⇒cosA-sinA = √2sinA

hope this helps you
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1402Aryan1402: instead of converting sin^2@+cos^2@ into 1 . i converted sin^2@ into 1-cos^2@ and cos^2@into 1-sin^2@

1402Aryan1402: then i rearranged the equation

1402Aryan1402: to get the desired result

RaGhAv200407: to say u can solve this in a more simpler and short way.

RaGhAv200407: @prasanthrai its correct! and to tell these type of questions are important once

RaGhAv200407: it should be √2sinA instead of only √2 in 'To show' side

Answered by RaGhAv200407

HERE IS YOUR ANSWER NO NEED OF ANY SQUARING,SIMPLE ,
HOPE IT HELPS YOU.

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