Question

hey guys please answer my question and I'll mark u brainliest

Answer 1

HOPE it HELPS YOU ....

Answer 2

let AB be the tower and BC be the flag post let OA equals x meters , AB equals y meters and BC equals h meters

in ΔOAB

tan a=AB/OA=y/x

x=y/tan a.....1

in Δ OAC

tan b=AC/OA= (y+h)/x

x=(y+h)/tan b......2

from 1 and 2

y/tana=(y+h)/tanb

ytanb=ytana+htana

y(tanb-tana)=htana

y= htana/(tanb-tana)

hence height of tower is htana/(tanb-tana)

hence proved

hope this helps you