hey guys please answer my question and I'll mark u brainliest
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Question :-
2x² - 2√x + 1 = 0.
Solution :-
2x² - 2√x + 1 = 0
=> 2x² - ( √2x + √2x) + 1 = 0
=> 2x² - √2x - √2x + 1 = 0
=> √2x ( √2x - 1) - 1 ( √2x - 1) = 0
=> ( √2x - 1) ( √2x - 1) = 0
=> √2x - 1 = 0. & √2x - 1 = 0
=> x = 1 / √2. & x = 1/ √2.
2x² - 2√x + 1 = 0.
Solution :-
2x² - 2√x + 1 = 0
=> 2x² - ( √2x + √2x) + 1 = 0
=> 2x² - √2x - √2x + 1 = 0
=> √2x ( √2x - 1) - 1 ( √2x - 1) = 0
=> ( √2x - 1) ( √2x - 1) = 0
=> √2x - 1 = 0. & √2x - 1 = 0
=> x = 1 / √2. & x = 1/ √2.
PrashantRai2810:
like you have solved
ok
carry on
trying
question is wrong
hyy
Answered by
1
that is the correct question and also the correct answer
the expert team can't be wrong ok....
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