Question

hey guys please answer my question and I'll mark u brainliest

Answer 1

Consider ΔABD.

∠ADB = 90°

∠ABD = 60°

∠BAD = 30°

∴ BD : AD : AB = 1 : √3 : 2

$BD : AD = 1 : \sqrt{3} \\ \\ \\ \frac{BD}{AD} = \frac{1}{\sqrt{3}} \\ \\ \\ AD = BD\sqrt{3} \\ \\ AD^2=(BD\sqrt{3})^2 \\ \\ AD^2=3BD^2$

Hence proved!

Hope this helps. Please mark it as the brainliest. ^_^

Please ask me if you've any doubt.

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#adithyasajeevan

                   

Answer 2

hope it will help you