Question

hey guys please answer my question, itZ urgent ​

Answer 1

Given:

• Resistance of lamp = 100Ω
• Resistance of toaster = 50Ω
• Resistance of water filter = 500Ω
• Are connected to 200V source
• The lamp , toaster & filter are connected in parallel

To find:

• Current of electric iron which is connected to the same source

Solution:

Let

• Resistance of lamp be R₁
• Resistance of toaster be R₂
• Resistance of water filter be R₃

❶ Total resistance

Since , the resistance is connected in parallel

So,

1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₚ = 1/100 + 1/50 + 1/500

1/Rₚ = 16/500

Rₚ = 500/16 = 31.25 Ω

❷ Current of electric iron

Using

V = I × R

Simplifying

I = V/R

♦ I = 200/31.25

♦ I = 7.04 A

Answer 2

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