hey guys please answer my question with proper steps and I'll mark u brainliest
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Anonymous:
sexxxy
hi
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hey guys please answer my question with proper steps and I'll mark u brainliest
Attachments:
see again hope now you understand clearly .
boobs
for find hole value of answer in term of p , so i find value of cisA
we find , in another page see i attached there cos = 2p/p²+1
its ok
Answered by
1
sec + tan = p
As sec^2 - tan^2 = 1
sec+ tan )( sec - tan ) = 1
sec - tan = 1/p
So add both
2 sec = p + 1/p
sec = p + 1/p)/2
1/cos = p + 1/p)/2
1/√1 - sin^2 = p + 1/p)/2
squaring
1/1- Sin^2 = ( p+ 1/p)^2/4
4/ ( p^2 + 1/p^2 + 2) = 1 - sin^2
sin^2 = 1 - 4/ ( p^2 + 1/p^2 +2)
sin^2 = P^2 + 1/p^2 + 2 - 4)/ p^2 + 1/p^2 +2
= p^2 + 1/p^2 -2)/ ( p+ 1/p)^2
= (p -1/p)^2/ ( p+ 1/p)^2
sin A =+- ( p - 1/p)/ p +1/p
= p^2 - 1)/ p^2 +1
cosec A = p^2 +1)/ p^2 -1
As sec^2 - tan^2 = 1
sec+ tan )( sec - tan ) = 1
sec - tan = 1/p
So add both
2 sec = p + 1/p
sec = p + 1/p)/2
1/cos = p + 1/p)/2
1/√1 - sin^2 = p + 1/p)/2
squaring
1/1- Sin^2 = ( p+ 1/p)^2/4
4/ ( p^2 + 1/p^2 + 2) = 1 - sin^2
sin^2 = 1 - 4/ ( p^2 + 1/p^2 +2)
sin^2 = P^2 + 1/p^2 + 2 - 4)/ p^2 + 1/p^2 +2
= p^2 + 1/p^2 -2)/ ( p+ 1/p)^2
= (p -1/p)^2/ ( p+ 1/p)^2
sin A =+- ( p - 1/p)/ p +1/p
= p^2 - 1)/ p^2 +1
cosec A = p^2 +1)/ p^2 -1
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