Math, asked by Anonymous, 1 year ago

hey guys please answer my question with proper steps and I'll mark u brainliest

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Answered by yosha20
2

Let θ = x

cos x  + sin x =  √2 cos x

squaring on both side, we get......

cos2x + sin2x + 2cosxsinx = 2cos2x

2sinxcosx = 2cos2x - cos2x - sin2x

2sinxcosx = cos2x - sin2x

2sinxcosx = (cosx+sinx) (cosx - sinx)

2sinxcosx = (root2 cosx) (cosx - sinx)

2sinxcosx/root2 cosx = cosx - sinx

 √2 sinx = cosx - sinx

hope it hlps u


yosha20: yeah
yosha20: i will tell u
yosha20: it is given the question na
yosha20: it is just the substitution if cos x + sin x
yosha20: from the question
Answered by brijeshpbhkmgm8
3

Answer:

here your answer dear.....

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