hey guys please answer this. Two wires have lengths, resistance and resiativities each in ratio 1:2. what is the ratio of their diameters?
1) 1:2
2)1:4
3)4:1
plzzzzz write the process?
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R = ρl/π(r2)²= 4ρl/π(d2)²
R1/R2 = 4ρ1l1/π(d1)²/4ρ2l2/π(d2)²
=(ρ1l1/(d1)²)((d2)²/ρ2l2)
= (ρ1/ρ2)(l1/l2)((d2)²/(d1)²)
1/2 = (1/2)(1/2((d2)²/(d1)²)
((d2)²/(d1)²) = 2
d2/d1 = √2
d1/d2 = 1/√2
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your answer is in the attachment!!❎❎
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