Question

Hey guys✌✌
please do it with substitution method

Answer 1

➡HERE IS YOUR ANSWER⬇

Given that :

0.2x + 0.3y = 1.3 .....(i)

and

0.4x + 0.5y = 2.3 .....(ii)

From (i), we get :

$x = \frac{1.3 - 0.3y}{0.2} \: \: ......(iii)$

Putting this value in (ii), we get :

$0.4( \frac{1.3 - 0.3y}{0.2} ) + 0.5y = 2.3 \\ \\ or \: \: 0.52 - 0.12y + 0.1y = 0.46 \\ \\ or \: \: 0.02y = 0.06 \\ \\ or \: \: y = 3$

Putting y = 3 in (iii), we get :

$x = \frac{1.3 - (0.3 \times 3)}{0.2} = 2$
Therefore, the required solution is

x = 2 and y = 3.

⬆HOPE THIS HELPS YOU⬅