hey Guys please give answer
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3
theta = 45°
Now,
tan^2 theta + 1/sin^2 theta
= (1)^2 + 1/(1√2)^2
= 1 + 1/1/2 = 1+2 = 3
because, tan 45° = 1
and, sin 45° = 1/√2
Now,
tan^2 theta + 1/sin^2 theta
= (1)^2 + 1/(1√2)^2
= 1 + 1/1/2 = 1+2 = 3
because, tan 45° = 1
and, sin 45° = 1/√2
dhruvsh:
clear kar dete hain
Answered by
0
=(1)^2+1/(1/2)^2
=1+4
=5
=1+4
=5
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