hey guys ..please help..anyone who solve this right will be surely marked as brainalist ...thank u sooo much
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Answered by
1
Answer:
Ok.. wait let me solve.. and then I am sending you..!
Answered by
1
Answer:
5
Step-by-step explanation:
AB=8cm
CD=6cm
PQ=1cm
Let radius of the circle be r
Therefore,
OA=OC=r
We know that the perpendicular dripped from the centre of the circle on the chord bisects the chord.
Therefore,
CQ=QD=3cm
AP=PB=4cm
Let OP=x
=>OQ=x+1
Now,
OA
2
=OP
2
+AP
2
=>r
2
=x
2
+4
2
=>r
2
=x
2
+16 (i)
OC
2
+OQ
2
+CQ
2
=>r
2
=(x+1)
2
+3
2
=>r
2
=x
2
+2x+1+9
=>x
2
+16=x
2
+2x+1+9 (from (i)
=>2x=6
=>x=3
Therefore,
r
2
=3
2
+16
=>r
2
=9+16
=>r
2
=25
=>r=5cm
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