Question

hey guys please help me ​

Answer 1

Answer:

PH = 3.28

PH = -LoG {H^+}

{H+} = 10 ^-PH

{H+} =10^-3.28

= 1.0 x 10 ^-3.28......................(1).

{H+} + {OH-} = 1.0 X 10^-14...........(2).

So..ConcenTraTioN OF OH-

FroM EquaTioN ..(1).

{OH-} = 1.0 x 10^-14/{H+}

FroM EquaTioN ...(2).

{OH-} = 1.0 x 10^-14 / 1.0 x 10^-3.28

= 5.2480746e - 18

WILL Be.=5.3 x 10 ^-10 M