Question

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Answer 1

Answer:

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Answer 2

$\color{red}{QUESTION}$

A bullet initially moving with a velocity 20 m/s strikes a target and comes to rest after penetrating a distance of 10cm in the target. Calculate the retardation caused by the target.

$\color{blue}{ANSWER}$

Given:

Initial velocity, u = 20 m/s

Final velocity, v = 0 m/s and s = 10 cm = 0.1 m

We use the third equation of motion: v² = u² + 2as

=> 0= (20)² + 2 x a x 0.1

=> 400 = - 0.2a

=> a = -2000 m/s2

This is the acceleration of the bullet.

The retardation is the negative value of the acceleration.

Thus, the retardation of the bullet is 2000 m/s2

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