hey guys,
please help me!
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I hope this helps you!
@vaibhav246
@vaibhav246
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since the sum of interior angles of triangle is 180° that gives angle B = 180° - 90° - 30°
angle B = 60°
now sinB = AC/AB
sin 60° = AC / 40
√3/2 = AC /40
AC = 20√3
similarly
cos B = BC / AB
cos 60° = BC/AB
1/2 = BC /40
BC = 20
hope it helps.
angle B = 60°
now sinB = AC/AB
sin 60° = AC / 40
√3/2 = AC /40
AC = 20√3
similarly
cos B = BC / AB
cos 60° = BC/AB
1/2 = BC /40
BC = 20
hope it helps.
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