Math, asked by ashamonikakati2, 1 year ago

hey guys , please help me...

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Anonymous: kor pora paiso ai question to Asamoni ??

ashamonikakati2: 2016-17 nagaon r test ppr

Anonymous: ohh thike ase moi o paisilu , ajiloi answer poa nai

ashamonikakati2: ohh

Anonymous: Agoto try korisu , akou a bar sai ding ro

ashamonikakati2: sua sn

Answers

Answered by ananyadesaignailcom

$1 \div \ \cos(0) - \tan(0) \\ 1(1 \div \cos(0) - \sin(0) \div \cos(0) \\ 1(1 - \sin(0) \div \cos(0) \\ = \cos(0 \div 1 - \sin(0) \\ = \sin2(0) + \cos2(0) = 1 \\ \cos2(0) = 1 - \sin2(0) \\ \cos(0) . \cos(0) = (1 - \sin(0)) (1 + \sin(0 \\ \cos(0 ) \div 1 - \sin(0) = 1 + \sin(0 ) \div \cos(0 \\ \cos(0 \div 1 - \sin(0) ) = 1 + \sin(0) - \cos(0 ) \div \cos(0 ) - (1 - \sin(0) \\ \cos(0) \div 1 - \sin(0 ) = 1 + \sin(0 - \cos(0 ) \div \cos(0) - 1 + \sin(0) \\ \sin(0) - \cos(0) + 1 \div \sin(0) + \cos(0) - 1 = 1 \div \cos(0) - \tan(0)$

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