Question

Hey guys please help me. Don't answer if you don't know anything about it or otherwise i will report you. Whoever answered me in a right way would be marked as BRAINLIEST. Find the greatest integer which on dividing 398,436 and 542leaves remainder 3,11 and 15 respectively. Kindly answer.​

Answer 1

Answer:

one remainder is not 3 I think it will be 7

according to seven answer is

according

→ 17 .

Step-by-step explanation :-

We have ,

→ The number 398, 436 and 542 which when divides by a positive integers leaves remainder as 7, 11, and 15 respectively .

→ Clearly, the required number divides ( 398 - 7 ) = 391 , ( 436 - 11 ) = 425, and ( 542 - 15 ) = 527 exactly .

•°• Required number = HCF( 391, 425, 527 ) .

Now,

→ 391 = 17 × 23 ,

→ 425 = 5² × 17 ,

→ 527 = 17 × 31 .

\therefore∴ HCF( 391, 425, 527 ) = 17 .

Hence, the required number is 17 .

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