Question

Hey guys!!! ✅✅✅

Please help me in doing this...... Tomorrow is my exams..... plz help me....

Right answer will be mark as Brainliest answer ✅✅✅


Don't spam ✅✅✅​

Answer 1

4(x-y)²-12(x-y)+9 = 0

4(x-y)²-6(x-y)-6(x-y)+9 = 0

2(x-y)[2(x-y)-3]-3[2(x-y)-3] = 0

[2(x-y)-3].[2(x-y)-3] = 0

2(x-y)-3 = 0

2(x-y) = 3

x-y = $\frac{3}{2}$

Answer 2

Step-by-step explanation:

4(x-y)²-12(x-y)+9 = 0

4(x-y)²-6(x-y)-6(x-y)+9 = 0

2(x-y)[2(x-y)-3]-3[2(x-y)-3] = 0

[2(x-y)-3].[2(x-y)-3] = 0

2(x-y)-3 = 0

2(x-y) = 3

x-y = \frac{3}{2}

2

3