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A student focussed image of a candle flame on a screen using a convex lens and noted down that position of screen is 88cms Find the focal length. Where will the image formed is he shifts candle towards lens at the position of 31cms.
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given:
object distance=u=12-50=-38cm
image distance =v=88-50=38cm
by using lens formula:
1)1/f=1/v-1/u
1/f=1/38+1/38=2/38
therefore, f=19cm
2) v=?
if u=31-50=-19cm
f=19cm
1/f=1/v-1/u
1/v=1/f+1/u
1/19-1/19
so, V=infinity, the image will be formed at infinity as the object is kept at the focus.
3)As the object is shifted towards lens, the object distances thus decreases and so we would see a variation in image nature,the image will be virtual,erect and magnified.
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