Question

Hey guys!!!!!

Please help me with this question

An inductive circuit contains a resistance of 10 ohms and an inductance of 2 H. If an AC voltage of 120 V and frequency 60 Hz is applied to this circuit,the current would be nearly
(a) 0.72 A
(b) 0.16 A
(c) 0.48 A
(d) 0.80 A

Please answer with detailed explanation...NO SPAMS please!!!​

Answer 1

Z= √R^2 + XL^2

= √100 + w^2 L^2

frequency= 60

w= 2 pie f = 120 pie = 376.8

Z= √100+ (376.8)^2 ×4

= √100 +567912.96 = √568012.96

= 753.6

V= IZ

I= V/Z

= 120/753.6 = 0.159

B)

Answer 2

Answer:

Your answer is option b