Physics, asked by MrudulaB, 1 year ago


Hey guys please help. The question is eating my head.
More than one option is correct.

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Answers

Answered by gohan
1
Hello sir , According to your question

Here ,it is mentioned that Qa , Qb are

Position at point A and B

And sir your question is saying , the

electric field strength to the right of

charge Qb on that line

Which passes through the two

charges which is showing in figure


Now sir your question is saying that

the distance between these two

charges Qa and Qb is L


And sir here is mentioned that

electric field is positive if the direction

concides with the direction on the x

axis


Now we understand the question

what our question is asking now I will

solve your question sir one by one sir :-)

It is showing that graph of Qa is

Upward with respect to ELECTRIC

FIELD VS DISTANCE GRAPH IF SO

sir I think ,

F= kq1q2/r^2

And sir E = F/q which means ,

E = kq/R^2

So here Ea= kQa/r^2 and r=L which

means sir,

Ea= kQa/L ^ 2 sir I want to tell you

one thing that graph is moving

upward with respect to electric field

and distance which means charge

Qa. Is positive sir and we know that

E is directly proportional to charge so

Sir => Qa is positive and similarly Qb

Is negative because graph is

Downward the axis so I think sir

Option b is correct

Now sir in option 3

Qa/Qb = (1+x)^2/x^2

Sir now I am proving this it is correct or not

We know that Ea = kQa / x^ 2

And Eb = kQb/ x2^2 now sir we need

to find the distance I think sir

x2 = x+L and we got

Now Eb = kQb/(x+L) ^2

Sir we have to find the ratio of Qa/Qb

We will Divide Ea/Eb we will get

Ea/. Eb = Qa(x+L)^2 / Qb( x^2)

And here it is come that if Ea= Ebwe get

Qa/Qb = x^2/(1+L)^2 so option C is incorrect





MrudulaB: Could be. I will be knowing the answer next month. I will check it. Thanks... n I m not sir, I am a girl.
gohan: Oh sorry mam :-) regards brainly helper
MrudulaB: That's fine sir.
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