Question

hey guys please solve these ☹​

Answer 1

Answer:

We know,

If a + b + c = 0 then, a³ + b³ + c³ = 3abc

Because a³ + b³ + c³ = 1/2(a + b + c ) (a² + b² + c² - ab - bc - ca)

Now, when a + b + c = 0 then, a³ + b³ + c³ - 3abc = 0

so, a³ + b³ + c³ = 3abc

Here, x + y + 2 = 0

so, x³ + y³ + 2³ = 3xy(2)

x³ + y³ + 8 = 6xy [ans]

Step-by-step explanation:

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Answer 2

We know,

If a + b + c = 0 then, a³ + b³ + c³ = 3abc

Because a³ + b³ + c³ = 1/2(a + b + c ) (a² + b² + c² - ab - bc - ca)

Now, when a + b + c = 0 then, a³ + b³ + c³ - 3abc = 0

so, a³ + b³ + c³ = 3abc

Here, x + y + 2 = 0

so, x³ + y³ + 2³ = 3xy(2)

x³ + y³ + 8 = 6xy [ans]