Hey guys please solve this question
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★angle P+angle S=180°(sum of adjacent angle of llgm is 180°)
→1/2angle P+1/2angle S=180/2
→angle PSB + angle SPB =90°
★In ∆PSB
★angle PSB + angle SPB + angle PBS=180°
→90°+ angle PBS =180°
→Angle PBS=90°
★Angle ABC= angle PBS(Vertically opposite angle)
→Angle ABC=90°
★Similarly In ∆RDQ
→angle RDQ=90°
★Angle ADC=angle RDQ
→Angle ADC=90°
★angle P+angle S=180°(sum of adjacent angle of llgm is 180°)
→1/2angle P+1/2angle S=180/2
→angle PSB + angle SPB =90°
★In ∆PSB
★angle PSB + angle SPB + angle PBS=180°
→90°+ angle PBS =180°
→Angle PBS=90°
★Angle ABC= angle PBS(Vertically opposite angle)
→Angle ABC=90°
★Similarly In ∆RDQ
→angle RDQ=90°
★Angle ADC=angle RDQ
→Angle ADC=90°
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