Question

Hey guys please solve this question

In the following figure ABCD is a rectangle with sides 8 cm and 4 cm. Find areas of ∆ ABC and a∆ CDA.

Answer 1

Answer:

Step-by-step explanation:

first find the line ac bu Pythagoras theorem

(H)^2= (B)^2 + (P)^2

h^2 = 8^2+ 4^2

h^2 = 64 + 16

h^2 = 80

h = 9

AC = 9

now, let find the area of cda

as it is a rectangle so opposite sides are equal

AD = BC

AB = CD

Thus ,

a of triangle = (1÷2) × b × h

= (1÷2) × 4 ×8

= 1÷2 × 32

= 16

hence area of triangle is 16

hope you had got it and plz click on thanks

Answer 2

Area of ∆ABC = 1/2 × base × height
= 1/2 × 8 × 4
= 16 cm²
Area of ∆ CDA is same as that of area of ∆ ABC,
So, Area of ∆ CDA = 16 cm²
Hope it may help you !!!!!