Hey guys please... Solve this question
No spam
Answers
#ANSWERWITHQUALITY #BAL
Step-by-step explanation:
[Please see the attached figure]
Let the speed of the car which starts from A be x km/hr. and the speed of the car which starts from B be y km/hr.
According to the given problem,
When the two cars move in the same direction they meet at point C (say) after 8 hrs.
∴ In 8 hr., Distance covered by the car which starts from place A is AC = 8x km.
∴ In 8 hr., Distance covered by the car which starts from place B is BC = 8y km.
[∵ Distance = Speed x Time]
∴ AC - BC = 80
=>8x - 8y = 80
=>8(x - y) = 80
=> x - y = 10 -----------(i)
When the two cars move in the same direction they meet at point C (say) after 1 hr. 20 min. = 4/3 hr. [∵ 1 hr.20 min = (1 + 20/60) hr. =(1 + 1/3) hr.=4/3 hr.]
∴In 4/3 hr., Distance covered by the car which starts from place A is AC = 4x/3 km.
∴ In 4/3 hr., Distance covered by the car which starts from place B is BC = 4y/3 km.
∴AC + BC = 80
=>(4x/3) + (4y/3) = 80
=>4x + 4y = 240
=>4(x + y) = 240
=>x + y = 60 ----------(ii)
On Adding equation (i) and (ii), We get,
x - y + x + y = 60 + 10
=>2x = 70
=> x = 35
Putting the value of x in (ii), We get,
35 + y = 60
=>y = 60 - 35
=>y = 25
∴Speed of the car which starts from A is 35 km/hr.
& Speed of the car which starts from B is 25 km/hr.
_____________________
//Hope this will Helped You//
//Please Mark it as Brainliest//
