Question

Hey Guys!!

Please solve this question of 11th standard

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Answer 1

Hey there!

Given,

Mass of bullet (m) = 40 g = 40 * 10⁻³ kg

Velocity of bullet ( v) = 1200 m/s

Max. force which can be exerted (F) = 144 N

Let no. of bullets fired per second be x.

From Newton's second law:

Force  = Rate of change of momentum

or, F = x(mv) / t

then, x = Ft / mv

x = (144 N × 1 s) / (40 × 10⁻³ kg × 1200 m/s)

x = 3

Hence, no. of bullets that can be fired per second are 3.

Answer 2

Explanation:

Given : m=40 g =0.04 kg v=1200 m/s F=144 N

Let n be the number of bullets that can be fired per second.

The force exerted by man must balance the change in momentum of the bullets per second.

∴ F=mnv

OR 144=0.04×v×1200 ⟹n=3 bullets per second