Question

Hey guys please tell me the full solution for this question ​

Answer 1

Answer:

hope this helps plz mark as brailiest

Answer 2

P=I2R

the current was increased by 100percent...

=I+100I/100=2I

P'=(2I)2R

=4I2R

percentage of current power as at disipitation..

=p'-p/p*100percent

=4I2R-I2R/I2R.100...(4I2R subtract from I2R)

=3I2R/I2R.100percent....(I2R and I2R get cancelled by numerator and denominator property)

=3.100percent

=300percentage

hence :option (c) is correct answer

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