Question

hey guys please tell me the value of k

Answer 1

1000 os correct answer

Answer 2

Roots are alfa=a and beta =b
So given that a-b=11
Now fm eqn x^2-5x+3(k-1)
a+b=-b/a=5,ab=3(k-1)
(a+b)^2=5^2
a^2+b^2+2ab=25
a^2+ b^2=25-2*(3(k-1)=25-6(k-1)
Now
(a-b) ^2=11^2
a^2+b^2-2ab=121
25-6k+1-2*3(k-1)=121
25-6k+1 - 6k+6=121
-12k=89
K=-89/12