Question

☺☺☺hey guys please try to do this plz plz plz because there is my exam on Monday so que is!!

An isosceles right triangle has area 168 cm^2 . If the altitude of ∆ is 24 cm , what is ☺the length of hypotenuse??☺☺

Answer 1

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Answer 2

Given, Area = 168 cm^2.

Given Altitude h = 24 cm.

We know that Area of triangle = (1/2) * b * h

⇒ 168 = (1/2) * b * 24

⇒ 168 = 12b

⇒ b = 168/12

⇒ b = 14 cm.

Let the hypotenuse be x.

Now,

According to Pythagoras theorem,

⇒ x^2 = (b/2)^2 + h^2

⇒ x^2 = (14/2)^2 + (24)^2

⇒ x^2 = 49 + 576

⇒ x^2 = 625

⇒ x = 25 cm.

Therefore, The length of hypotenuse = 25 cm.

Hope this helps!