Question

hey guys plezz one ques help me plezz​

Answer 1

Step-by-step explanation:

the answer is being attached

Answer 2

Given :

Length of the rectangle is 4cm more than breadth.

Perimeter of the rectangle : 80cm

To find :

The area of the rectangle.

Solution :

Let the length be x + 4 cm.

Let the breadth be x cm.

First, we will find the value of breadth by the formula of perimetre of the rectangle.

Breadth of the rectangle :

$\sf \dashrightarrow {Perimetre}_{(Rectangle)} = 2 \: (Length + Breadth)$

$\sf \dashrightarrow 80 = 2 \: \{ (x + 4) + x) \}$

$\sf \dashrightarrow 80 = 2 \: (2x + 4)$

$\sf \dashrightarrow 80 = 4x + 8$

$\sf \dashrightarrow 4x + 8 = 80$

$\sf \dashrightarrow 4x = 80 - 8$

$\sf \dashrightarrow 4x = 72$

$\sf \dashrightarrow x = \dfrac{72}{4}$

$\sf \dashrightarrow x = 18 \: cm$

Now, let's find the length of the rectangle.

Length of the rectangle :

$\sf \dashrightarrow x + 4$

$\sf \dashrightarrow 18 + 4$

$\sf \dashrightarrow 22 \: cm$

Now, let's find the answer of this question i.e, the area of the rectangle.

Area of the rectangle :

$\sf \dashrightarrow Length \times Breadth$

$\sf \dashrightarrow 22 \times 18$

$\sf \dashrightarrow 396 \: cm$

Hence, the area of the rectangle is 396 cm.