hey guys plezz one question help mee plezz
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(i) Based on the △ ABE and △ ACF We know that ∠ AEB = ∠ AFC = 90o It is given that BE = CF From the figure we know that ∠ A is common for both ∠ BAE and ∠ CAF So we get ∠ BAE = ∠ CAF = ∠ A Therefore, by ASA congruence criterion we get △ ABE ≅ △ ACF (ii) As we know that △ ABE ≅ △ ACF It is proved that AB = AC.Read more on Sarthaks.com - https://www.sarthaks.com/717609/in-the-given-figure-be-and-cf-are-two-equal-altitudes-of-abc-show-that-i-abe-acf-ii-ab-ac
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