Math, asked by amulya1092, 8 months ago

Hey guys.... pls answer me these 2 questions....if u don't know the answer don't try to answer..for the sake of points because I have mathematics test tmrw...


1.The number 8000 is first increased by 20% and then decreased by 20%.Find the resulting number

2.The number 12000 is first decreased by 25% and then increased by 25%.Find the resulting number

answer me....pls​

Answers

Answered by aadityavarma2005
1

Answer:1st one

Step-by-step explanation:

(8000×20)/100=1600

8000+1600=9600

(9600×20)/100=1920

9600-1920=7680

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2nd

The resulting = The original number x (1 - (25/100)) x (1 + (25/100)) = 12000 x (75/100) x (125/100) = 11,250

Answered by Thanusri
1

1. Number 8000 is increased by 20%=8000*20/100=800*2=1600

=8000+1600=9600

Then decreased by 20%=9600*20/100

=960*2=1920

=9600-1920=7680

2. Number 12000 decreased by 25%

=12000*25/100=12000/4=3000

=12000-3000=9000

Number increased by 25%=9000*25/100=2250

=9000+2250=11250

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