Question

HEY GUYS.... PLS ANSWER THIS...☺️☺️​

Answer 1

$\bold {\huge {Your ~answer :-}}$

$\bf\huge\boxed{10\:sec}$

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Solution—

Given—

Initial speed of ball = 49 m/s

Now,

Let after time body reaches the highest point.

Time of ascent = Time of descent

So, total time taken to return the ball his hand = 2t

Use Kinematics equation

$v = u + at$

=> 0 = 49 - 9.8t

=> t = 5 sec

Hence, time taken to return his hand = 2×5 = 10 sec

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