Question

hey guys ❤️
pls help..

if a + b + c = 10 and a³ + b³ + c³= 80 find the value of a3 + b3 + c3 – 3abc



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Answer 1

Answer:

a+b+c=9 and a

2

+b

2

+c

2

=35

Using formula,

(a+b+c)

2

=a

2

+b

2

+c

2

+2(ab+bc+ca)

9

2

=35+2(ab+bc+ca)

2(ab+bc+ca)=81−35=46

(ab+bc+ca)=23

using formula,

(a

3

+b

3

+c

3

)−3abc=(a

2

+b

2

+c

2

−ab−bc−ca)(a+b+c)

a

3

+b

3

+c

3

−3abc=(35−23)×9=9×12=108

Answer (B) 108

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Answer 2

here is your answer hope this will help you dude