Question

hey guys pls help me....​

Answer 1

Answer:

[L ^1T ^−1]

Explanation:

F=A cosBx+C sinDt

The argument, θ of cos or sin should be dimensionless.

therefore,

dimension of Bx = [MLT]

[B][L']=[MLT]

[B]=[ML^0T]

Similarly [D][T′]=[MLT]

[D]=[MLT^0

dimension of DB= [MLT^O] ÷ [ML^OT]

= [L ^1T ^−1]