hey guys pls help me with this.
can you pls tell me how did x ^3 , y ^3 and z ^3 come in the end step
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Answered by
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if you take the LCM of the denominator
you will get x, y, z
in order to get x, y, z you should also multiply
the numerators then you will get all the 3 cubes in the numerator
Answered by
1
Answer:
LCM of the three fraction is XYZ,
first fraction = z²/xy => to make its denominator xyz, you have to multiply both Nr and Dr with z,
=> z²/xy × z/z = z³/xyz
similarly with 2nd fraction x²/yz × x/x => x³/xyz
and 3rd fraction y²/zx × y/y => y³/xyz
now as you have common denominator xyz,
sum of the three fraction becomes
(z³+x³+y³) / xyz
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