Hey guys pls help me with this question :-)
I already know the answer , that's why I'm expecting detailed answers only :-)
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Answers
(i). Value of 'x'
In ∆ADC,
40° + 50° + (2x + 20°) = 180°
(Angle sum property of triangle)
110° + 2x = 180°
2x = 180° - 110°
2x = 70°
x = 35°
(ii). Measure of angle DAB
(2x + 10°) + 40°
(2 × 35° + 10°) + 40°
(70° + 10°) + 40°
80° + 40°
•°• Angle DAB = 120°
(iii). Measure of angle BCD
BCD = BCA + ACD
•°• (x - 20°) + 50°
(35° - 20°) + 50°
15° + 50°
•°• Angle BCD = 65°
(iv). Measure of angle ABC
(2x + 25°) + Angle ABC = 180°
(Linear Pair)
Angle ABC = 180° - (2x + 25°)
180° - (2 × 35° + 25°)
180° - (70° + 25°)
180° - 95°
•°• Angle ABC = 85°
Hope this was helpful
Answer:
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