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Answer:
In ∆ABD and ∆ACD,
AB=AC (given)
AD=AD (common)
BD=CD (given AD is the bisector)
So, ∆ABD is congruent to ∆ACD on SSS rule.
By CPCT, angle ADB = angle ADC
But BDC is a straight line, so angle ADB+angle ADC = 180°
Which implies angle ADB=90°
Hence proved.
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