Question

hey Guys pls solve the give problems.....
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Answer 1

Step-by-step explanation:

REFER TO ATTACHMENT.......

Answer 2

Hii its tom85

cos 3A /cosA =1/2

4cos^3 - 3cosA/cosA = 1/2

4cos^2A = 7/2

4 - sin^2A = 7/2

sin^2A = 1/2

sin A = 1/sqrt2

since

sin3A = 3sinA - 4 sin^3 A

now

sin3A /sinA= 3 - 4sin^2A

sin3A/sinA = 3 - 2 = 1

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hope it may helps you