Question

Hey Guys,


pls solve this pls
and pls see x is not equal to 0 and -1​

Answer 1

Answer:

see the photo attached and mark brainliest

Answer 2

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\bf\pink{ \mapsto \: \frac{x}{x + 1} + \frac{x + 1}{x} = \frac{34}{15} } \\ \\ \bf\pink{ \mapsto \: \frac{ {x}^{2} + {(x + 1)}^{2} }{x(x + 1)} = \frac{34}{15} } \\ \\ \bf\pink{ \mapsto \: \frac{ {x}^{2} + {x}^{2} + 2x + 1}{ {x}^{2} + x } = \frac{34}{15} } \\ \\ \bf\pink{ \mapsto \: \frac{ {2x}^{2} + 2x + 1}{ {x}^{2} + x } = \frac{34}{15} } \\ \\ \bf\pink{ \mapsto \:15( {2x}^{2} + 2x + 1) = 34( {x}^{2} + x ) } \\ \\ \bf\pink{ \mapsto \: {30x}^{2} + 30x + 15 = 34 {x}^{2} + 34x } \\ \\ \bf\pink{ \mapsto \: 34 {x}^{2} + 34x - {30x}^{2} - 30x - 15 = 0 } \\ \\ \bf\pink{ \mapsto \: {4x}^{2} + 4x - 15 = 0} \\ \\ \bf\pink{ \mapsto \: {4x}^{2} + (10x - 6x) + 15 } \\ \\ \bf\pink{ \mapsto \: {4x}^{2} + 10x - 6x - 15 = 0} \\ \\ \bf\pink{ \mapsto \: 2x(2x + 5) - 3(2x + 5) = 0} \\ \\ \bf\pink{ \mapsto \: (2x + 5)(2x - 3) = 0} \\ \\ \bf\green{ \implies \: 2x + 5 = 0 }\\ \bf\red{ \implies x = \frac{ - 5}{2} } \\ \\ \bf\purple{ \implies 2x - 3 = 0} \\ \bf\orange{ \implies \: x = \frac{3}{2} }$

$\\ \large\boxed{ \fcolorbox{red}{violet}{hope \: it \: help \: you}}$