Question

Hey! Guys plz ans this ques.

Answer 1

This is the actual answer to this question . See the picture.

please vote my answer

Answer 2

Answer:

Step-by-step explanation:

lets, secθ + cosecθ = q

= (1/sinθ) + (1/cosθ) = q

= (sinθ + cosθ)/sinθcosθ) = q

= [p/sinθcosθ] = q

= sinθcosθ = p/q ----- (1)

now Consider, sinθ + cosθ = p

sqring b/s,v get

(sinθ + cosθ)2 = p2

= sin2θ + cos2θ + 2sinθcosθ = p2

= 1 + 2(p/q) = p2 ----------frm =n 1

= (q + 2p)/q = p2

= (q + 2p) = p2q

= 2p = p2q – q

= 2p = q(p2 – 1)

=q(p2 – 1)=2p

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