Hey! Guys plz ans this ques.
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This is the actual answer to this question . See the picture.
please vote my answer
please vote my answer
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m just confused
y u thanked me,as i didt help u
cause you marked my answer as the brainliest
yes i got it
without me it was imposible
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Answer:
Step-by-step explanation:
lets, secθ + cosecθ = q
= (1/sinθ) + (1/cosθ) = q
= (sinθ + cosθ)/sinθcosθ) = q
= [p/sinθcosθ] = q
= sinθcosθ = p/q ----- (1)
now Consider, sinθ + cosθ = p
sqring b/s,v get
(sinθ + cosθ)2 = p2
= sin2θ + cos2θ + 2sinθcosθ = p2
= 1 + 2(p/q) = p2 ----------frm =n 1
= (q + 2p)/q = p2
= (q + 2p) = p2q
= 2p = p2q – q
= 2p = q(p2 – 1)
=q(p2 – 1)=2p
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thnxx
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