hey guys plz answer iwill give u 10 points
5ka 2) plzz
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If a/b=b/c
ac=b2
(a2+ b2)(b2+ c2)
=a2b2+a2c2+b4+b2c2
=a2b2+(ac)2+b4+b2c2
Replacing ac=b2
= a2b2+(b2)2+b4+b2c2
=a2b2+b4+b4+b2c2
=a2b2+2b4+b2c2
=b2(a2+2b2+c2)
Replacing b2 with ac
=b2(a2+2ac+c2)
=b2(a+c)2
={b(a+c)}2
=(ab+bc)2
Hence proved.
ac=b2
(a2+ b2)(b2+ c2)
=a2b2+a2c2+b4+b2c2
=a2b2+(ac)2+b4+b2c2
Replacing ac=b2
= a2b2+(b2)2+b4+b2c2
=a2b2+b4+b4+b2c2
=a2b2+2b4+b2c2
=b2(a2+2b2+c2)
Replacing b2 with ac
=b2(a2+2ac+c2)
=b2(a+c)2
={b(a+c)}2
=(ab+bc)2
Hence proved.
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