HEY GUYS,PLZ ANSWER THIS QUESTION RIGHTLY,I'LL MARK IT BRAINLIEST:- An object is kept at a distance of 18cm,20cm22cm and 45cm respectively from a lens of power +5D. a)In which case or cases will you get a magnified image? b)Which of the magnified image can be obtained on screen?
Priyanshu3008:
plzzzz help!!!
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Power=+5D
so the lens is convex
P=1/f
f=1/5 m
f=20 cm
so in each case
1/v-1/u=1/f
1/v=1/u +1/f
v=uf/(u+f)
v=20u/(20+u)
now u varies from
-18,-20, -22,-30 cm
so,
v=-180 cm
if u=-18 cm
so, magnification is (v/u)=+10
similarly
v=+220 cm if u=-22 cm
so magnification (v/u)=-10
v=+60 cm ,if u=-30 cm
so magnification is (v/u)=-2
if u=-20 cm
v=infinity
so the magnification=-infinity
now magnification is positive in 1st case
where u=-18 cm
all the other images can be obtained on screen
so the lens is convex
P=1/f
f=1/5 m
f=20 cm
so in each case
1/v-1/u=1/f
1/v=1/u +1/f
v=uf/(u+f)
v=20u/(20+u)
now u varies from
-18,-20, -22,-30 cm
so,
v=-180 cm
if u=-18 cm
so, magnification is (v/u)=+10
similarly
v=+220 cm if u=-22 cm
so magnification (v/u)=-10
v=+60 cm ,if u=-30 cm
so magnification is (v/u)=-2
if u=-20 cm
v=infinity
so the magnification=-infinity
now magnification is positive in 1st case
where u=-18 cm
all the other images can be obtained on screen
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