Question

Hey guys plz give me ans correctly don't spam I will report​

Answer 1

its sideways and i am disabled, so turn it upside down...

Answer 2

Step-by-step explanation:

Let ABCD be a quadrilateral a circle with centre 0

Now join AO,BO,CO,DO

from the figure ΔDAO = ΔBAO = 1

Also ΔABO= ΔCBO ( since, BA & BC are tangents)

Let ΔABO=ΔCBO=2

similarly we take the same way for vertices C & D

Sum of the angles at the center is 360degrees

Recall that sum of the angles in quadrilateral, ABCD=360degrees

=2(1+2+3+4)=360degrees

=1+2+3+4=180degrees

in ΔAOB, ΔBOA=180(1+2)

inΔCOD, ΔCOD=180(3+4)

ΔBOA +ΔCOD=360(1+2+3+4)=360-180 =180

since AB & CD subtend supplementary angles at 0

thus opposite sides of a quadrilateral cirumscribing a circle subtend supplementary angles at the center of the circle